(PHP 5 >= 5.3.0, PHP 7, PHP 8)
This FAQ is split into two sections: common questions, and some specifics of implementation that are helpful to understand fully.
First, the common questions.
\my\name
or \name
resolve?
my\name
resolve?
name
resolve?
name
resolve?
There are a few implementation details of the namespace implementations that are helpful to understand.
use
statement.
No. Namespaces do not affect any existing code in any way, or any as-yet-to-be-written code that does not contain namespaces. You can write this code if you wish:
示例 #1 Accessing global classes outside a namespace
<?php
$a = new \stdClass;
This is functionally equivalent to:
示例 #2 Accessing global classes outside a namespace
<?php
$a = new stdClass;
示例 #3 Accessing internal classes in namespaces
<?php
namespace foo;
$a = new \stdClass;
function test(\ArrayObject $typehintexample = null) {}
$a = \DirectoryIterator::CURRENT_AS_FILEINFO;
// extending an internal or global class
class MyException extends \Exception {}
?>
示例 #4 Accessing internal classes, functions or constants in namespaces
<?php
namespace foo;
class MyClass {}
// using a class from the current namespace as a type hint
function test(MyClass $typehintexample = null) {}
// another way to use a class from the current namespace as a type hint
function test(\foo\MyClass $typehintexample = null) {}
// extending a class from the current namespace
class Extended extends MyClass {}
// accessing a global function
$a = \globalfunc();
// accessing a global constant
$b = \INI_ALL;
?>
\my\name
or \name
resolve?
Names that begin with a \
always resolve to what they
look like, so \my\name
is in fact my\name
,
and \Exception
is Exception
.
示例 #5 Fully Qualified names
<?php
namespace foo;
$a = new \my\name(); // instantiates "my\name" class
echo \strlen('hi'); // calls function "strlen"
$a = \INI_ALL; // $a is set to the value of constant "INI_ALL"
?>
my\name
resolve?
Names that contain a backslash but do not begin with a backslash like
my\name
can be resolved in 2 different ways.
If there is
an import statement that aliases another name to my
, then
the import alias is applied to the my
in my\name
.
Otherwise, the current namespace name is prepended to my\name
.
示例 #6 Qualified names
<?php
namespace foo;
use blah\blah as foo;
$a = new my\name(); // instantiates "foo\my\name" class
foo\bar::name(); // calls static method "name" in class "blah\blah\bar"
my\bar(); // calls function "foo\my\bar"
$a = my\BAR; // sets $a to the value of constant "foo\my\BAR"
?>
name
resolve?
Class names that do not contain a backslash like
name
can be resolved in 2 different ways.
If there is
an import statement that aliases another name to name
, then
the import alias is applied.
Otherwise, the current namespace name is prepended to name
.
示例 #7 Unqualified class names
<?php
namespace foo;
use blah\blah as foo;
$a = new name(); // instantiates "foo\name" class
foo::name(); // calls static method "name" in class "blah\blah"
?>
name
resolve?
Function or constant names that do not contain a backslash like
name
can be resolved in 2 different ways.
First, the current namespace name is prepended to name
.
Finally, if the constant or function name
does not exist
in the current namespace, a global constant or function name
is used if it exists.
示例 #8 Unqualified function or constant names
<?php
namespace foo;
use blah\blah as foo;
const FOO = 1;
function my() {}
function foo() {}
function sort(&$a)
{
sort($a);
$a = array_flip($a);
return $a;
}
my(); // calls "foo\my"
$a = strlen('hi'); // calls global function "strlen" because "foo\strlen" does not exist
$arr = array(1,3,2);
$b = sort($arr); // calls function "foo\sort"
$c = foo(); // calls function "foo\foo" - import is not applied
$a = FOO; // sets $a to value of constant "foo\FOO" - import is not applied
$b = INI_ALL; // sets $b to value of global constant "INI_ALL"
?>
The following script combinations are legal:
file1.php
<?php
namespace my\stuff;
class MyClass {}
?>
another.php
<?php
namespace another;
class thing {}
?>
file2.php
<?php
namespace my\stuff;
include 'file1.php';
include 'another.php';
use another\thing as MyClass;
$a = new MyClass; // instantiates class "thing" from namespace another
?>
There is no name conflict, even though the class MyClass
exists
within the my\stuff
namespace, because the MyClass definition is
in a separate file. However, the next example causes a fatal error on name conflict
because MyClass is defined in the same file as the use statement.
<?php
namespace my\stuff;
use another\thing as MyClass;
class MyClass {} // fatal error: MyClass conflicts with import statement
$a = new MyClass;
?>
PHP does not allow nesting namespaces
<?php
namespace my\stuff {
namespace nested {
class foo {}
}
}
?>
<?php
namespace my\stuff\nested {
class foo {}
}
?>
use
statement.
The only elements that are affected by use
statements are namespaces
and class names. In order to shorten a long constant or function, import its containing
namespace
<?php
namespace mine;
use ultra\long\ns\name;
$a = name\CONSTANT;
name\func();
?>
It is very important to realize that because the backslash is used as an escape character within strings, it should always be doubled when used inside a string. Otherwise there is a risk of unintended consequences:
示例 #9 Dangers of using namespaced names inside a double-quoted string
<?php
$a = new "dangerous\name"; // \n is a newline inside double quoted strings!
$obj = new $a;
$a = new 'not\at\all\dangerous'; // no problems here.
$obj = new $a;
?>
Any undefined constant that is unqualified like FOO
will
produce a notice explaining that PHP assumed FOO
was the value
of the constant. Any constant, qualified or fully qualified, that contains a
backslash will produce a fatal error if not found.
示例 #10 Undefined constants
<?php
namespace bar;
$a = FOO; // produces notice - undefined constants "FOO" assumed "FOO";
$a = \FOO; // fatal error, undefined namespace constant FOO
$a = Bar\FOO; // fatal error, undefined namespace constant bar\Bar\FOO
$a = \Bar\FOO; // fatal error, undefined namespace constant Bar\FOO
?>
Any attempt to define a namespaced constant that is a special, built-in constant results in a fatal error
示例 #11 Undefined constants
<?php
namespace bar;
const NULL = 0; // fatal error;
const true = 'stupid'; // also fatal error;
// etc.
?>